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-9.8x^2+4.9x+1=0
a = -9.8; b = 4.9; c = +1;
Δ = b2-4ac
Δ = 4.92-4·(-9.8)·1
Δ = 63.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.9)-\sqrt{63.21}}{2*-9.8}=\frac{-4.9-\sqrt{63.21}}{-19.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.9)+\sqrt{63.21}}{2*-9.8}=\frac{-4.9+\sqrt{63.21}}{-19.6} $
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